381,006 views
30 votes
30 votes
Hello! May I please have some assistance working this through step by step?

Hello! May I please have some assistance working this through step by step?-example-1
User Simon ML
by
2.7k points

1 Answer

15 votes
15 votes

To determine the number of different 4-person committees that can be made out of 15 students, let's use the Combination Formula.


nCr=(n!)/(r!(n-r)!)

where n = the total number of choices and r = the total number of selections.

In the question, our n = 15 because there are 15 students to choose from. Our r = 4 because 4 selections will be made from 15 students.

Let's replace the variables in the formula with their corresponding numerical value.


_(15)C_4=(15!)/(4!(15-4)!)

Then, solve. Here are the steps.

1. In the denominator, subtract 15 and 4 first.


_(15)C_4=(15!)/(4!11!)

2. Expand 15! until 12 only and cancel 11! Expand 4! too.


_(15)C_4=(15*14*13*12)/(4*3*2*1)

3. Multiply the numbers in the numerator and denominator.


_(15)C_4=(32,760)/(24)

4. Divide the numerator by the denominator.


_(15)C_4=1,365

Therefore, there are 1, 365 different ways of forming a 4-person committee out of 15 students.

User TunaMaxx
by
2.6k points