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Find the vertex of this parabola y=-x^2+8x-25
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Find the vertex of this parabola
y=-x^2+8x-25

User Margot
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1 Answer

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dy/dx=-2x+8

dy/dx=0 when -2x+8=0, 2x=8, x=4

y(4)=-16+32-25=-9

So the vertex is (4,-9)
User Yanery
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