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If cosa = -4/5 with a in QIII. Find sin2a

User Dharga
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30 is the answer of the question good luck
User Edymerchk
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Since a is in the third quadrant, both sina and cosa are negative.

Now, sin(2a) can be rewritten as 2sin(a)cos(a).
Thus, we can find sin(a) by using Pythagoras' Theorem.


cos(a) = -(4)/(5)

Now, by focusing on the positive value, we can see that 5 is the hypotenuse.
Let the missing side be x.
x² + 16 = 25
x² = 9
x = 3, because x > 0


\text{Thus, } sin(a) = -(3)/(5)

Substituting these into the equation, we get:

2sin(a) cos(a) = 2 \cdot -(3)/(5) \cdot -(4)/(5)

2sin(a) cos(a) = (24)/(25)


\therefore sin(2a) = (24)/(25)
User Bob Sanders
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