Answer : The molecular geometry of interior carbon atom is tetrahedral.
Explanation :
Now we have to determine the hybridization of the given molecule.
Formula used :
![\text{Number of electron pair}=(1)/(2)[V+N-C+A]](https://img.qammunity.org/2018/formulas/chemistry/college/zia3jm1s1xbt3kxm0r43raz35v736wepqh.png)
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
The given molecule is,

In this compound, the interior atom or central atom is carbon and
,
and 2 hydrogen atoms are neighboring atoms.
![\text{Number of electrons}=(1)/(2)* [4+4]=4](https://img.qammunity.org/2018/formulas/chemistry/college/cxsedm4go9bd1gwy18as0n6kvc6x3pdiov.png)
Number of bond pairs = 4
Number of lone pairs = 0
The number of electron pair are 4 that means the hybridization will be
and the electronic geometry and the molecular geometry of the molecule will be tetrahedral.
Hence, the molecular geometry of interior carbon atom is tetrahedral.