Question

A beaker contains nickel(ii sulfate, zinc(ii sulfate and solid iron. what species in this beaker will be reduced?

Answer 1

Nickel (II) to solid nickel.

Step-by-step explanation:

Hello,

In this case, the placed species are nickel (II) sulfate
`NiSO_4`, zinc sulfate
`ZnSO_4` and solid iron
`Fe`. Now, as the nickel sulfate is more reactive than the zinc sulfate, it will experience the following reduction half-reaction from nickel (II) to solid nickel:

`Ni^(2+)+2e^--->Ni^0`

Nevertheless, it is possible that the zinc might experience the same reduction reaction from zinc (II) to solid zinc as well.

Best regards.

Answer 2

If a beaker is contained with the substances nickel sulfate, zinc sulfate and solid iron, there is a substance that will be reduced in the following substances that is in it. The substance that will be reduced as it is in the beaker is the Ni^2 + or also known as the Nickel (II)