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How do you solve a(3x-8)=b-18x
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How do you solve a(3x-8)=b-18x

User GBrian
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\displaystyle a(3x-8)=b-18x\\\\3ax-8a=b-18x\\\\3ax+18x=b+8a\\\\3x(a+6)=b+8a\\\\3x= (b+8a)/(a+6)\quad, a\\e-6\\\\x= (b+8a)/(3(a+6))
User CIAvash
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