Question

To put it in graphing form and then graphY=x^2-6x+3

Answer 1

We have the following:

`\begin{gathered} y=x^2-6x+3 \\ f(x)=x^2-6x+3 \end{gathered}`

now, we must give values to x, to be able to graph

`\begin{gathered} f(-2)=x^2-6x+3=(-2)^2-6\cdot-2+3=19 \\ f(-1)=x^2-6x+3=(-1)^2-6\cdot-1+3=10 \\ f(0)=x^2-6x+3=(0)^2-6\cdot0+3=3 \\ f(1)=x^2-6x+3=(1)^2-6\cdot1+3=-2 \\ f(2)=x^2-6x+3=(2)^2-6\cdot2+3=-5 \end{gathered}`

The grahp is: