Answer:
from x = 0 to x = 2π :-
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Explanation:
To find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)=4cos(2x -π)
now, f'(x) = 0
- 4sin(2x − π) =0
sin (2x − π) =0
2x − π = kπ ... k in Z
In general x=(k+1)π/2
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =2 then x= 3π/2
X-coordinates of maximum points are x = π/2 and x= 3π/2