Question

(Quadratic) What is the answer to this quadratic

Answer 1

`x_(1) = (2+√(192))/(-4); x_(2) = (2-√(192))/(-4)`

Explanation:

`-2a^(2)-2b-12=0\\`

Take the coefficients and substitute for a, b and c

`a = -2; b = -2; c = -12`

`x_(1,2) = (-b +- √(b^2 - 4ac) )/(2a)`

`x_(1,2) = (2+-√(2^2-4*-2*-12))/(2*-2)`

`x_(1) = (2+√(192))/(-4)`

`x_(2) = (2-√(192))/(-4)`

Please tell me if my solutions are incorrect so I can fix them.

Answer 2

2a^2+2b-12=0 is not a solvable quadratic. I will assume you meant 2x^2+2x-12
The quadratic formula is (-b+-sqrt(b^2-(4ac))/2a

(-2+-sqrt(2^2-(4*2*-12))/2*2
(-2+-sqrt(4-(-96))/4
(-2+-sqrt(100))/4
(-2+-10)/4
12/4 or 8/4
3 or 2
The answer is x=3 or x=2