Question

What volume of carbon monoxide gas at STP reacts to produce 759 g of iron?

Answer 1

The volume of Carbon Monoxide gas at STP reacts to produce 759 g of Iron is 458 L.

If this is the Given:
`Fe_(2) O_(3) + CO` >>>
`Fe+ CO_(2)`

Then the first step is to balance it:

`2 Fe_(2) O_(3) + 6 CO` >>>
`4 Fe+ 6 CO_(2)`
Afterwards, we convert 759 g of Iron to moles of Carbon Monoxide (CO).

`759 g Fe * (1 mol Fe)/(55.65g Fe) * (6 mol CO)/(4 mol Fe) = 20.45822102 mol CO`
Lastly, we find the volume of carbon monoxide gas at STP, where one mole of gas occupies 22.4 Liters.

`20.45822102 mol CO * (22.4 L of CO)/(1 mol CO) = 458.2641509 L of CO`
Since there are only 3 significant figures, so we round the answer to 458 L.