Register
A gas at 20.0°C and 52.1 mL is heated to 93.5°C. What is the new volume?
177k views
4 votes
A gas at 20.0°C and 52.1 mL is heated to 93.5°C. What is the new volume?

User Sytech
by
6.8k points

1 Answer

2 votes

( V_(1) )/( T_(1) ) =
( V_(2) )/( T_(2) )

V_(1) = 0.0521 L

T_(1) = 293.15 K

T_(2) = 366.65 K

Solve for
V_(2)


(0.0521 L)/(293.15 K) =
\frac { V_(2) }{366.65 K}


V_(2) = 0.06516 L or 65.2 mL
User Wolf Paulus
by
7.6k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.5m questions

11.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Which of the following statements does not describe a physical property of a piece of chalk A. Chalk is solid B.chalk can be broken into pieces C. Chalk is white D. Chalk will bubble in vinegar
Link Copied!