Question

a gas sample is heated from -20 to 57 C and the volume is increased from 2.00 L to 4.50 L. If the initial pressure is 0.109 atm, what is the final pressure?

Answer 1

According to the combined gas laws we can write P1*V1/T1 =P2*V2/T2.we have initial pressure which is P1=0.109atm.Initial vol V1=2litres and initial temperature is -20 degree C which is 273-20K i.e.,T1=253K.and final volume isV2= 4.50 litres and final temp is 57 degree C which is 273+57K i.e.,T2=330K so according to the question we need to find out P2.which is 0.109*2*330÷4.50*253=0.0632atm which is the final pressure.