Question

A solution has a [OH−] of 1 x 10−12 M. What is the [H3O+] of the solution? a1 x 10−14 M b1 x 10−2 M c2 M d14 M

Answer 1

b. 1 x 10⁻² M.

Step-by-step explanation:

Let's see the following formula, which represents the dissociation constant:

`[OH^-]=[H_3O^+]=1\cdot10^(-7)\text{ M}.`

If we multiply each [OH -] and [H3O +] concentrations, we obtain:

`[OH^-][H_3O^+]=1\cdot10^(-14)\text{ M}^2.`

As we have [OH -] = 1 x 10⁻¹² M, if we solve for [H3O +] and replace the value of the concentration of [OH -] we obtain:

`[H_3O^+]=(1\cdot10^(-14)M^2)/([OH^-])=(1\cdot10^(-14)M^2)/(1\cdot10^(-12)M)=1\cdot10^(-2)M=0.01\text{ M.}`

The [H3O +] of the solution would be b. 1 x 10⁻² M.