Question

A cork is floating in salty water. As more salt is added to the water to increase its density, the cork will

Answer 1

the answer is Float higher

Answer 2

Float more above the water level

Step-by-step explanation:

As we know that during flotation of the force balance equation is given as

`F_g = F_b`

weight of the cork is balanced by the buoyancy force due to liquid

so here we can say

`mg = \rho V g`

V = volume of submerged part of the cork

now we have

`V = (m)/(\rho)`

now as we add more salt in the water then the density of water will increase due to which the submerged part of the volume will decrease as we know that it is inversely depends on density of the water

so here submerged volume will decrease so cork will float more part above the liquid level