Question

Kim surveyed the students at her school to find out if they like hotdogs and/or burgers. The table below shows the results of the survey:

If a student likes hotdogs, what is the probability that student also likes burgers?

A- 93.8%

B- 50.7%

C- 42.1%

D- 39.5%

Answer 1

the answer is 42.1% that is pretty easy

Answer 2

Answer: C- 42.1%

Explanation:

Let H represents the event of liking hotdogs, B represents the event of liking burger and S represents total number of students,

Thus, by the given table,

n(H) = 76, n(S) = 150,
`n(H\cap B) = 32`

⇒
`P(H)=(n(H))/(n(S))=(76)/(150)`

Also,

`P(H\cap B) = (n(H\cap B))/(n(S))= (32)/(150)`

Thus, by the definition of conditional probability,

The probability of liking burger when it is given that the student likes the hotdgs,

`P((B)/(H))=(P(H\cap B))/(P((H))`

`=(32/150)/(76/150)`

`=(32)/(76)`

`=0.421052632`

`=42.1052632\%\approx 42.1\%`

⇒ Option C is correct.