138k views
0 votes
A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder contain? (Given: R = 8.314 L∙kPa/K∙mol)

2 Answers

5 votes

Answer:

for plato its 106.32mL

Step-by-step explanation:

User Iraklisg
by
8.3k points
2 votes
In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given
P = 10130.0 kPa
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT PV
---- ------ ---> n = --------
RT RT RT

10130.0 kPa x 50 L
n= ---------------------------------------------
8.314 L. kPa/K.mol x 573.15 K
506,500
= ----------------------------
4,765.17 mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles
User Masaki Hara
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.