Question

Oxygen has a density of 1.43 g/l at stp. what is the density of oxygen at 1.30 atm?

Answer 1

At STP means Pressure= 1 atm and Temp= 273K

Density= mass/volume=grams/L
M= molar mass
P= pressure
R= gas constant
T= temp

Density= PM/RT

Density= (1.30 atm x 32 grams/mol)/(0.0821 x 273K)= 1.86 g/L

Answer 2

Step-by-step explanation:

It is given that pressure is 1.30 atm.

So, at STP temperature will be 273.15 K. And, according to the ideal gas equation:

PV = nRT ........ (1)

And, Density =
`(mass)/(volume)`

or, Volume =
`(mass)/(Density)` ....... (2)

Putting equation (2) is equation (1) we get the following.

PV = nRT

`P * (mass)/(Density) = nRT`

Molar mass of oxygen is 32 g/mol. Now, putting the given values into the above equation to calculate density as follows.

`P * (mass)/(Density) = nRT`

`1.30 * (32 g/mol)/(Density) = 1 * 0.0821 L atm/mol K * 273.15 K`

Density =
`(41.6)/(22.42)` g/L

= 1.855 g/L

Thus, we can conclude that density of oxygen at 1.30 atm is 1.855 g/L.