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Identify the vertex for the graph of y = 2x2 + 8x − 3.

User IngoB
by
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2 Answers

5 votes
Vertex: (-2, -11)
Focus: ( -2 -87/8)
Axis of Symmetry: x = -2
Directrix: y = -89/8

X / Y
-4/ -3
-3/-9
-2/-11
-1/-9
0/-3

Identify the vertex for the graph of y = 2x2 + 8x − 3.-example-1
User Astropringles
by
7.3k points
4 votes

Answer:

The vertex of the given parabola is (-2,-11).

Explanation:

The given function is


y=2x^2+8x-3 .... (1)

The general for of a parabola is


y=ax^2+bx+c .... (2)

then the vertex of the parabola is


(-(b)/(2a),f((-b)/(2a)))

From (1) and (2), we get


a=2,b=8,c=-3


-(b)/(2a)=-(8)/(2(2))=-2

Put x=-2 in the given function.


y=2(-2)^2+8(-2)-3=-11

Therefore the vertex of the given parabola is (-2,-11).

User Mallikarjuna
by
8.0k points

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