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I need help with this please check work when finished WHICH GRAPH IS CORRECT

I need help with this please check work when finished WHICH GRAPH IS CORRECT-example-1
User Lorah Attkins
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1 Answer

24 votes
24 votes

Answer:

The piecewise function is given below as


f(x)=\begin{cases}(x+3)^2+2;x\leq-2 \\ -2x+4,;-2<strong>Step 1:</strong><p>The first function is given below as</p>[tex]\begin{gathered} f(x)=(x+3)^2+2 \\ \text{when x=2} \\ f(2)=(-2+3)^2+2 \\ f(2)=1^2+2 \\ f(2)=1+2=3 \\ (-2,3) \end{gathered}

Hence, the graph above is a parabola that is opened upwards because the coefficient of the leading term is greater than 1, and it will be shaded at point (-2,3) because of the less than or equal to sign

(it has a negative slope that is as x-increase, y decreases, and vice versa)

Step 2:

The second function is given below as


\begin{gathered} f(x)=-2x+4 \\ \text{when x=-2} \\ f(-2)=-2(-2)+4 \\ f(-2)=4+4 \\ f(-2)=8 \\ (-2,8) \\ \\ f(x)=-2x+4 \\ \text{when x=-4} \\ f(-4)=-2(-4)+4 \\ f(-4)=8+4 \\ f(-4)=12 \\ (-4,12) \end{gathered}

The second equation is a straight line that will be open at points (-2,8) and (4,12) because of the strictly less than sign

Step 3:

The thrid function is


\begin{gathered} f(x)=3x-15;x\ge4 \\ \text{when x=4} \\ f(4)=3(4)-15 \\ f(4)=12-15 \\ f(4)=-3 \\ (-3,4) \end{gathered}

The equation above is a straight line and will be shaded at point (-3,4) because of the greater than or equal to sign

(it has a positive slope that is as x increases,y also increases and vice versa)

Hence,

The final answer will be

I need help with this please check work when finished WHICH GRAPH IS CORRECT-example-1
User Rocketas
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2.7k points