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What is the law of sines

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4 votes

Solving for Angles


\displaystyle (sin∠C)/(c) = (sin∠B)/(b) = (sin∠A)/(a)

Make sure to use
\displaystyle sin^(-1)towards the end, or elce you will throw your answer off!

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Solving for Edges


\displaystyle (c)/(sin∠C) = (b)/(sin∠B) = (a)/(sin∠A)

I am joyous to assist you at any time.

User Jck
by
8.1k points
5 votes


(a)/(sin A) = (b)/(sin B) = (c)/(sin C)for any triangle:


User Jermyn
by
7.7k points

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