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37 votes
Use the quadratic formula to solve the problem: y=2x²+4x-6be sure to show all your work

User Infamous
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1 Answer

14 votes
14 votes

x\text{ =}\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

That above is the quadratic formula where

a = 2

b = 4

c = -6


x=\frac{-4\pm\sqrt[]{4^2-4*2*-6}}{2*2}
\begin{gathered} x\text{ = }\frac{-4\pm\sqrt[]{16+48}}{4} \\ x=\frac{-4\pm\sqrt[]{64}}{4} \\ x\text{ = }(-4\pm8)/(4) \end{gathered}
\begin{gathered} x\text{ =}\frac{-4\text{ + 8}}{4\text{ }}=(4)/(4)=1 \\ or \\ x\text{ = }(-4-8)/(4)=(-12)/(4)=-3 \end{gathered}

User Volksman
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