Question

How to do number 13 and 14

Answer 1

From the information: v is 64 while c is 5

Differentiate the new equation h=-16
`t^(2)` + 64t + 5 to get
`(dh)/(dt)`= -32t + 64.

no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs

no 14). put t as 2 sec in the equation: h=-16
`t^(2)` + 64t + 5. This gives

h=-16(
`2^(2)`) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft