Step 1:
Write the reaction and balance it
C3H8(g) + 5O2(g) => 4H2O(l) + 3CO2(g)
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Step 2
In STP conditions we know that: 1 mol of any gas (C3H8 in this case) = 22.4 L
1 mol C3H8 = 22.4 L (STP)
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Step 3
C3H8(g) + 5O2(g) => 4H2O(l) + 3CO2(g)
We proceed like this:
22.4 L (1 mol C3H8) ------ 3 x 22.4 L CO2 (1 mol CO2 = 22.4 L)
32.6 L C3H8 ------ X
X = 32.6 L C3H8 x 3 x 22.4 L CO2/ 22.4 L C3H8 = 97.8 L
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Answer: 97.8 L CO2