Question

What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?

Answer 1

Acceleration,
`a=10\ m/s^2`

Step-by-step explanation:

It is given that,

Mass of the cart, m = 30 kg

Thurst applied to the engine, F = 300 N

Let a is the acceleration of the cart. According to Newton's second law of motion, force is equal to the product of mass and acceleration. It is given by :

`F=ma`

`a=(F)/(m)`

`a=(300\ N)/(30\ kg)`

`a=10\ m/s^2`

So, the acceleration of the cart is
`10\ m/s^2`. Hence, this is the required solution.

Answer 2

Answer :
`a=10\ m/s^2`

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

`F = m* a`

a is the acceleration of the engine.

`a=(F)/(m)`

`a=(300\ N)/(30\ Kg)`

`a=10\ m/s^2`

So, the acceleration of the engine is
`10\ m/s^2`.

Hence, this is the required solution.