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Factor the following polynomial completely.

-x^2 y^2 + x^4 + 4y^2 - 4x^2

A) (x - 2)(x - 2)(x + y)(x - y)
B) (x + 2)(x + 2)(x + y)(x - y)
C) (x + 2)(x - 2)(x + y)(x - y

User Kevmc
by
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2 Answers

1 vote
i just took this question on a test and the answer was c
User Inkriti
by
8.3k points
4 votes

Answer: The correct option is (C)
(x+2)(x-2)(x+y)(x-y).

Step-by-step explanation: We are given to factorize the following polynomial completely :


P(x, y)=-x^2y^2+x^4+4y^4-4x^2.

We will be using the following the following factorization formula :


a^2-b^2=(a+b)(a-b).

The factorization of the given polynomial is as follows :


P(x, y)\\\\=-x^2y^2+x^4+4y^4-4x^2\\\\=x^4-x^2y^2-4x^2+4y^2\\\\=x^2(x^2-y^2)-4(x^2-y^2)\\\\=(x^2-4)(x^2-y^2)\\\\=(x^2-2^2)(x^2-y^2)\\\\=(x+2)(x-2)(x+y)(x-y).

Thus, the required factored form of the given polynomial is
(x+2)(x-2)(x+y)(x-y).

Option (C) is CORRECT.

User Vicrion
by
8.2k points

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