Question

Write an equation of the parabola that has the same shape as the graph of f(x)=8x^2, but with (1,8) as the vertex g(x)= ?

Answer 1

g (x) = 8(x - 1)² + 8

Explanation:

We have that the equation of the parabola with a center different from the origin is the following:

`\begin{gathered} y=(x-h)^2+k \\ \\ \text{ where \lparen h, k\rparen is the vertex } \end{gathered}`

In this case, (h,k) is equal to (1, 8), therefore:

`g(x)=8\left(x-1\right)^2+8`