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What are the factors of these two problems and how do you do the second one? 1. 32a^2 + 24b^2 2. 12a^2 –15ab –16a +20b

What are the factors of these two problems and how do you do the second one? 1. 32a^2 + 24b^2 2. 12a^2 –15ab –16a +20b
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What are the factors of these two problems and how do you do the second one?

1. 32a^2 + 24b^2
2. 12a^2 –15ab –16a +20b

User Mateusz Mrozewski
by
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1 Answer

4 votes
12a² –15ab –16a +20b = (12a² –15ab) –(16a -20b)

1st parenthesis : (12a² –15ab) = 3a(4a - 5b)

2nd parenthesis - (16a -20b) = - 4(4a -5b)

1st + 2nd = 3a(4a - 5b) - 4(4a -5b)

common factor (4a-5b) ==>hence (4a=5b)(3a-4)

User Mring
by
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