210k views
5 votes
Approximately how many times greater is 2.3 x 10^-4 than 1.15 x 10^8

User Picomancer
by
6.3k points

2 Answers

4 votes
It won't be any much greater since 2.3* 10^-4= 0.00023 and 1.15 * 10^8= 115000000 then you would have to subtract which will still give you 115000000...

User Kishia
by
6.5k points
5 votes

Answer:


2* 10^(-12)

Explanation:

We are given that two numbers are


2.3* 10^(-4) and
1.15* 10^8

We have to find that how many times greater
2.3* 10^(-4) than
1.15* 10^8 approximately.

In order to find that we divide
2.3* 10^(-4) by
1.15* 10^8


(2.3* 10^(-4))/(1.15* 10^8)


(2.3* 10^(-4))/(1.15* 10^8)={230* 10^(-4-8)


(2.3* 10^(-4))/(1.15* 10^8)=2* 10^(-12)


2.3* 10^(-4)=2* 10^(-12) times
1.15* 10^8

Hence,
2.3* 10^(-4) is
2* 10^(-12) times greater than
1.15* 10^8

User Jbindel
by
5.9k points
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