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What is the measure of BDC, given that figure ADCB is a rectangle?

What is the measure of BDC, given that figure ADCB is a rectangle?-example-1

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We are asked to solve for the angle of BDC in the figure which is rectangle ACBD.

Since it is a rectangle, each corner has a 90°. Initially, it was given that angle BDA is equal to 50°. Then we can solve for BDC, such as the solution is shown below:

90° = ∠ BDC + ∠ BDA
90° = ∠BDC + 50°
∠BDC = 90° - 50°
∠ BDC = 40°

The answer is 40°.
User PiQuer
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