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What is the function in point -slope form of the line passing through (1,9) and (-1, 11)

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Point-slope form is:

(y-y1)=m(x-x1)

So we first need to find the slope, m, which is (y2-y1)/(x2-x1)

m=(11-9)/(-1-1)=2/-2=-1, and we can use either point for y1 and x1, I'll use (1,9)

(y-9)= -1(x-1)
User Ben Clarke
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