Question

n the waiting room of a vet's office, there are 4 cats, 5 dogs, 1 lizard, and 1 hamster. A represents the event that a randomly selected animal in this waiting room is a dog. What is the probability of the complement of event A? Enter your answer as a fraction, in simplified form, in the box

Answer 1

the answer 5/11. you add all those numbers up (thats the denominator) and put the 5 representing a dog on top of the fraction

Answer 2

The probability is:

`(6)/(11)`

Explanation:

There are 4 cats, 5 dogs, 1 lizard, and 1 hamster.

A represents the event that a randomly selected animal in this waiting room is a dog.

This means that the probability of A is the ratio of number of dogs to the total number of animals.

i.e.

`P(A)=(5)/(11)`

( Since the total number of animals are: 11

and the total number of dogs=5 )

Also, the probability of complement of A is given by:

`P(A^c)=1-P(A)`

Hence,

`P(A^c)=1-(5)/(11)\\\\\\P(A^c)=(11-5)/(11)\\\\\\P(A^c)=(6)/(11)`

Hence, the answer is:

`P(A^c)=(6)/(11)`