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Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effective in pulling the sled horizontally along the ground?

User Shn
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1 Answer

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If we consider that the surface wherein this box is located is frictionless in such a way that the friction does not affect its motion, we can calculate for the horizontal force by multiplying the force with the sine of the angle.
x-component of force = (4 N) x (sin 62°)
= 3.53 N
User Joe Albahari
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