Question

Circle describe and correct each error 10v^2-46v=2010v^2-46v-20=02(5v^2-23v-10)=02(v-25)(c+2)=0V-25=0 and v+2=0V=25 and v=-2

Answer 1

Given:

The solved quadratic equation is given.

Required:

To describe and correct each error.

Answer:

Let us find the the error.

`\begin{gathered} 10\\u^2-46\\u=20 \\ 10\\u^2-46\\u-20=0 \\ 2(5\\u^2-23\\u-10)=0 \\ 5\\u^2-23\\u-10=0 \\ 5\\u^2-25\\u+2\\u-10=0 \\ 5\\u(\\u-5)+2(\\u-5)=0 \\ (\\u-5)(5\\u+2)=0 \\ (\\u-5)=0,(5\\u+2)=0 \\ \\u=5,5\\u=-2 \\ \\u=5,\\u=(-2)/(5) \end{gathered}`

Hence, the error is

`(\\u-25),(\\u+2)`

There should be

`(\\u-5),(5\\u+2)`

in the calculation.

Final Answer:

The error is

`(\\u-25),(\\u+2)`