Question

Right triangles ABC and DEF are inscribed in the same circle. They do not overlap. Where is the center of the circle located? A) at the point where a leg of ABC intersects a leg of DEF B) at the point where a leg of ABC intersects the hypotenuse of DEF C) at the point where the hypotenuse of ABC intersects a leg of DEF D) at the point where the hypotenuse of ABC intersects the hypotenuse of DEF

Answer 1

The correct answer is D.

Explanation:

When a right triangle is inscribed inside a circle, the hypotenuse of the triangle goes through the diameter. The answer is obvious even from this fact.

But if continue to apply the conditions of the question, we can observe that even we'll have one right triangle and one right isosceles triangle because the triangles don't overlap. The triangles will intersect at the hypotenuse because both of them are right triangle where the hypotenuse is a diameter.

Answer 2

My answer is: D) at the point where the hypotenuse of ABC intersects the hypotenuse of DEF

I only am assuming this scenario, a circle that has 2 right triangles that do not overlap either forms a square or rectangle inside the circle and the center of the circle is most likely located at the point where the hypotenuse of both triangles intersect.