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What are the solutions to 2x^2+7x=4?

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2x^2+7x-4=0

2x^2+8x-x-4=0

2x(x+4)-1(x+4)=0

(2x-1)(x+4)=0

So the zeros or solutions occur when x=-4 and 1/2
User Bhordupur
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