Answer:
Hence, the standard deviation(S.D.) to the nearest tenth is:
6.9
Explanation:
The steps for finding the standard deviation are:
- find the Mean (the simple average of the numbers)
- Then for each number: subtract the Mean and square the result.
- Then work out the mean of those squared differences.
- Take the square root of that and we are done.
so we will make it's table as:
Let μ denote the mean and X denote the entries.
X X-μ (X-μ)^2
33 -5.125 26.265625
37 -1.125 1.265625
42 3.875 15.015625
39 0.875 0.765625
25 -13.125 172.265625
51 12.875 165.765625
40 1.875 3.515625
38 -0.125 0.015625
μ=38.125.
Now Variance(V)=(Σ(X-μ)^2)/8=(384.875)/8=48.109375
Now square root of V is:6.936092091
So, √V=S.D.=6.9(to the nearest tenth)