Final answer:
The mass of 0.513 mol Al2O3, using the molar mass of 102.0 g/mol, is 52.3 g, expressed to three significant figures as this matches the least number of significant figures in the given data.
Step-by-step explanation:
The mass of 0.513 mol Al2O3 can be calculated by multiplying the number of moles of Al2O3 by its molar mass. The molar mass of Al2O3 is given as 102.0 g/mol. Therefore, the calculation would be:
Mass of Al2O3 = 0.513 mol × 102.0 g/mol = 52.326 g of Al2O3
When expressing the calculated mass, it is important to present it with the correct number of significant figures. Given that the molar mass has four significant figures and the number of moles (0.513) has three significant figures, the final answer should also have three significant figures, resulting in 52.3 g of Al2O3.