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What is the y value of the vertex of 4x^2+8x-8
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What is the y value of the vertex of 4x^2+8x-8
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Jun 15, 2018
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What is the y value of the vertex of 4x^2+8x-8
Mathematics
high-school
Pranjal Diwedi
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Pranjal Diwedi
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Vertex x=-b/2a
Ax^2+bx+c
X=-8/2 (4)
X=-8/8
X=-1
Plug in
4x^2+8x-8
4 (-1)^2+8 (-1)-8
4 (1)-8-8
4-8-8
-4-8
-12
Vertex= (-1,-12)
Jason Holloway
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Jun 15, 2018
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Jason Holloway
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3
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Vertex x=-b/2a
Ax^2+bx+c
X=-8/2 (4)
X=-8/8
X=-1
Plug in
4x^2+8x-8
4 (-1)^2+8 (-1)-8
4 (1)-8-8
4-8-8
-4-8
-12
Vertex= (-1,-12)
Yasir Majeed
answered
Jun 21, 2018
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Yasir Majeed
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