Question

Evaluate −7c2−7c−9/−7d when c=−2 and d=1. Enter an integer or a fraction.

Answer 1

Replace each variable with their respective values on the given expression to evaluate it:

`\begin{gathered} c=-2 \\ d=1 \\ \Rightarrow(-7c^2-7c-9)/(-7d)=(-7(-2)^2-7(-2)-9)/(-7(1)) \end{gathered}`

Use the order of operations to simplify the expression. On the numerator, solve for powers first:

`(-7(-2)^2-7(-2)-9)/(-7(1))=\frac{-7(4)^{}-7(-2)-9}{-7(1)}`

Then, solve for products both in the numerator and denominator:

`\frac{-7(4)^{}-7(-2)-9}{-7(1)}=\frac{-28^{}+14-9}{-7}`

Then, solve for additions and substractions from left to right:

`\begin{gathered} \frac{-28^{}+14-9}{-7}=(-14-9)/(-7) \\ =(-23)/(-7) \end{gathered}`

Finally, simplify the fraction using the law of signs:

`(-23)/(-7)=(23)/(7)`

Therefore, the answer is:

`(23)/(7)`