Question

A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

Answer 1

The answer is 8 cm.

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Answer 2

The surface area of the spherical biscuit is calculated through the equation,
A = 4πr²
We are given with one surface area, that is the amount of wrapper per biscuit.
200.96 = 4πr²
The value of r from the equation is 5.65 cm. A diameter is twice the value of the radius. Thus, the answer is 11.3 centimeters.