Specific Heat of Water= 4.186 J/g°C
Specific Heat of Ice = 2.00 J/g°C
Molar Heat of Fusion = 6030 J/mol
Molar Heat of Vaporization = 40790 J/mol
You take an ice cube (mass = 18g) from the freezer (T = -10ºC) and place it on the table. Later that day, you notice a puddle of water on the table that has reached ambient room temperature (20ºC). How much heat must have been absorbed to make this happen?
Your answer:
1867.0 J
2260.4 J
7897.0 J
42,657.0 J