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Evaluate 7 sigma notation n=1 2(-2)^n-1

User Suzanne
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2 Answers

6 votes

Answer:

the answer is D .86

Explanation:

User Luis Gouveia
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3 votes
This is a geometric of the form:

a(n)=2(-2)^(n-1)

And the sum of any geometric sum is:

s(n)=a(1-r^n)/(1-r) in this case:

s(n)=2(1-(-2^n))/(1--2)

s(n)=2(1-(-2^n))/3 so

s(7)=2(1-(-2^7))/3

s(7)=2(1--128)/3

s(7)=2(129)/3

s(7)=86
User Ano
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