Question

An employee earns $48,000 in the first year with a company. Every year, the annual salary increases by $4,500. How much is earned during eight years with the company? $388,500 $420,000 $510,000 $636,000

Answer 1

510,000

Explanation:

easier and faster way than above:

384000 (that is, 48,000 * 8) base

384000 + 4500 (salary) * (0 + 1 + 2 + 3 + 4 +5 +6 +7) (that's every day - 1) =

384000 +4500 * (28) =

384,000 + 126000 = 510,000

Answer 2

Since every year, the annual salary increases by $4,500, then in the second year the employee earns:

`48000+4500=52500.`

In the third year the employee earns:

`52500+4500=57000.`

In the fourth year, the employee earns:

`57000+4500=61500.`

In the fifth year, the employee earns:

`61500+4500=66000.`

In the sixth year, the employee earns:

`66000+4500=70500.`

`61500+4500=66000.`

In the seventh year, the employee earns:

`70500+4500=75000.`

Finally, in the eighth year, the employee earns:

`75000+4500=79500.`

Therefore, during eight years with the company the employee earned:

`\begin{gathered} 48000+52500+57000+61500+66000+70500+75000+79500 \\ =510000. \end{gathered}`

Answer: Third option $510,000.