Question

Find the equations of the line that passes trough point (3,4)and is perpendicular to the given line. 3x+2y=4

Answer 1

The point is given (3,4) and the line is given 3x+2y=4 which is perpendicular to the equation of line determined.

Then slope of the equation line is

`m=\frac{-1}{slope\text{ of perpendicular line}}`

The slope of perpendicular line is

`y=-(3)/(2)x+2`

slope is -3/2.

Then the slope od equation of line is

`m=-(1)/(-(3)/(2))=(2)/(3)`

Then the equation of line obtained is

`y=mx+c`
`4=(2)/(3)*3+c`
`4-2=c\text{.}`
`c=2`

The equation of line formed is

`y=(2)/(3)x+2`