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Find the area of parallelogram abcd given m a = 30 and the following measures. ad = in.; ab = 8 in. a= 16√3 in.² 32 in.² 32√3 in.²

User Makeiteasy
by
6.9k points

2 Answers

2 votes

Answer:

C) 32√3 in^2

Explanation:

Area of the parallelogram = base * height

Given: base = AB = 8 in.

We need to find the height using 30-60-90 triangle ratio 1: 2:√3

In this case, height = 8√3

Now we have to multiply base 8 and height 4√3

Area of the parallelogram =8 *4√3

= 32√3 in^2

Answer: C) 32√3 in^2

Hope this will helpful.

Thank you.

User Andrew Leap
by
7.0k points
4 votes

Answer:

The correct option is C. 32√3 inches²

Explanation:

Given : Base = AB = 8 inches

We need to find the height of the parallelogram :

m∠A = 30°

So, to find height use 30 - 60 - 90 triangle ratio 1 : 2 : √3

So, The side opposite to height is half of the base

⇒ Side opposite to height = 4 inches

⇒ Height is equal to the √3 times of its opposite side

⇒ Height = 4√3 inches

Area of the parallelogram = base × height

⇒ Area of the parallelogram = 8 × 4√3

= 32√3 inches²

Hence, The correct option is C. 32√3 inches²

User Chris Houghton
by
6.8k points
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