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What is the ph of a solution if [oh–] = 2.3 x 10–5 m?

What is the ph of a solution if [oh–] = 2.3 x 10–5 m?
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What is the ph of a solution if [oh–] = 2.3 x 10–5 m?

User George
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1 Answer

4 votes
pOH = -log[OH-] and pH + pOH = 14
So, all you have to do is take the negative log of 2.3*10^-5 and then subtract that number from 14 to find the pH
User Aron Ahmadia
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