Question

An ideal gas is contained in a container of volume V at temperature T. If the volume is doubled at a constant pressure, what will be the change in temperature?

Answer 1

The temperature will be doubled.

Answer 2

Answer: The temperature also get doubled.

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T` (At constant pressure and number of moles)

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1` = initial volume of gas = v

`V_2` = final volume of gas = 2v

`T_1` = initial temperature of gas = t

`T_2` = final temperature of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

`(v)/(t)=(2v)/(T_2)`

`T_2=2t`

Therefore, the temperature of the gas of will be twice of initial temperature.