Method to follow:
In the 1st exercise since both equations are equal to the same y, then we can write the here below equality:
0.048x²+5.2x = 1.12x+1.6. You transpose the right equation to the left:
==> 0.048x²+5.2x-1.12x-1.6 = 0
==> 0.048x²+4.08x-1.6=0
==> solve with [-b+-√(b²+4ac)]/2a
==> x'=0.3936 & x"=101.606
Plug x' & x" in any of the equation & you will get the respective value of
y' = 2.04 & y"=115.4
OR (0.39,2.04) & (101.61,115.4)
Apply the same logique for the other parts