A source charge generates an electric field of 4286 N/C at a distance of 2.5 m. What is the magnitude of the source charge? 1.2 µC 3.0 µC 1.2 C 3.0 C

Question

asked Jan 7, 2018 37.2k views

2 Answers

Kalamarico · Answer 1 · 2018-01-14T08:15:54+0000

Answer : Charge,
$q=3.0\ \muC$

Explanation :

It is given that :

Electric field,
$E=4286\ N/C$

Distance,
$r=2.5\ m$

We know that the electric field at any point is given by :

E=k(q)/(r^2)

k is the electrostatic constant.

q is the electric charge

r is the distance.

q=(E* r^2)/(k)

$q=(4286\ N/C* (2.5\ m)^2)/(9* 10^9\ Nm^2/C^2)$

$q=0.0000029\ C$

$q=2.9\ \mu C$

or

$q=3.0\ \mu C$

The correct option is (b).

Hence, this is the required solution.