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A group of friends will buy at most 8 snacks at the movie theater and spend no more than $42. they will pay $4 for each box of candy and $7 for each bag of popcorn. they system of inequalities graphed
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Nov 13, 2018
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A group of friends will buy at most 8 snacks at the movie theater and spend no more than $42. they will pay $4 for each box of candy and $7 for each bag of popcorn. they system of inequalities graphed below represents this information.
which combination of boxes of candy and bags of popcorn could the group buy?
a) 5 boxes of candy and 4 bags of popcorn
b) 3 boxes of candy and 4 bags of popcorn
c) 2 boxes of candy and 6 bags of popcorn
d) 8 boxes of candy and 1 bag of popcorn
Mathematics
high-school
Heath Borders
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The answer is B because you multiply 4 and 3 and get 12 then you multiply 7 and 4 and you get 28 then you add them together and get 40 so B is the correct answer.hope this helps
Mister Epic
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Nov 14, 2018
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Option B is correct, because 3 boxes of candy will cost $12 and 4 bags of popcorn will cost $28, adding the two gives us $40. They are only allowed to spend 42 dollar, so option B is the closest answer, the rest of the options are all above $42.
Unthinkingly
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Nov 19, 2018
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